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(5x+5)(2x+5)-10x^2=35x+25
We move all terms to the left:
(5x+5)(2x+5)-10x^2-(35x+25)=0
We get rid of parentheses
-10x^2+(5x+5)(2x+5)-35x-25=0
We multiply parentheses ..
-10x^2+(+10x^2+25x+10x+25)-35x-25=0
We get rid of parentheses
-10x^2+10x^2+25x+10x-35x+25-25=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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